
页面中的全部,在线,离线的筛选为自定义的样式,如何和后台交互呢
前端代码
<section class="flex flex-col sm:flex-row items-start sm:items-center gap-4 mb-6 animate-down delay-5">
<div class="relative">
<i class="fas fa-search absolute left-3 top-1/2 -translate-y-1/2 text-sm" style="color: #94A3B8;"></i>
<input type="text" class="search-box" placeholder="搜索设备名称、编号或患者..." id="searchInput" oninput="filterDevices()" aria-label="搜索设备">
</div>
<div class="flex items-center gap-2 flex-wrap filter-row" role="tablist" aria-label="状态筛选">
<button class="filter-btn active" data-filter="all" data-value="all" role="tab" aria-selected="true">全部</button>
<button class="filter-btn" data-filter="online" data-value="1" role="tab" aria-selected="false">在线</button>
<button class="filter-btn" data-filter="offline" data-value="0" role="tab" aria-selected="false">离线</button>
<!-- <button class="filter-btn" data-filter="warning" data-value="all" role="tab" aria-selected="false">低电量</button> -->
</div>
</section>
js代码//筛选
$(document).on("click", ".filter-btn", function () {
var value = $(this).data('value');
console.log(value)
var options = table.bootstrapTable('getOptions');
options.pageNumber = 1;
options.queryParams = function(params){
var filter = {};
var op= {};
if(value != 'all'){
filter['is_online'] = value;
op['is_online']= "=";
}
params.filter = JSON.stringify(filter);
params.op = JSON.stringify(op);
return params
};
table.bootstrapTable('refresh',{});
return false
});